I'm trying to assign a rank to the rows of a dataframe using a window function over a string column (user_id), based on alphabetical order. So, for example:
user_id | rank_num
-------------------
A |1
A |1
A |1
B |2
A |1
B |2
C |3
B |2
B |2
C |3
I tried using the following lines of code:
user_window = Window().partitionBy('user_id').orderBy('user_id')
data = (data
.withColumn('profile_row_num', dense_rank().over(user_window))
)
But I'm getting something like:
user_id | rank_num
-------------------
A |1
A |1
A |1
B |1
A |1
B |1
C |1
B |1
B |1
C |1
Partition by user_id
is unnecessary. This will cause all user_id
to fall into their own partition and get a rank of 1. The code below should do what you wanted:
user_window = Window.orderBy('user_id')
data = data.withColumn('profile_row_num', dense_rank().over(user_window))