I'm using uploadify (a jQuery uploading) script, which has basically a PHP file at the backend. I want to do some kind of debugging of PHP code, (for example see what kind of errors I get in the PHP file (when it's called by jQuery), but I don't know how I can print the errors. For example the original PHP file is:
<?php
if (!empty($_FILES)) {
$tempFile = $_FILES['Filedata']['tmp_name'];
$targetPath = $_SERVER['DOCUMENT_ROOT'] . $_GET['folder'] . '/';
$targetFile = str_replace('//','/',$targetPath) . $_FILES['Filedata']['name'];
move_uploaded_file($tempFile,$targetFile);
}
?>
Now for example I add a line before move_uploaded_file() in the above code.
die("die befor moving file");
When this PHP file is called by the script, it won't go to the next line but it wont print the message either. How can I print the error message? If it can't be done this way, can I display some javascript alert message. The idea is to know where the error in the PHP file is. Thanks.
Here's the front end uploading page code:
<script type="text/javascript">
$(document).ready(function() {
$("#fileUpload").fileUpload({
'uploader': 'uploadify/uploader.swf',
'cancelImg': 'uploadify/cancel.png',
'script': 'uploadify/upload.php',
'folder': 'files',
'multi': false,
'displayData': 'speed'
});
});
</script>
</head>
<body>
<fieldset style="border: 1px solid #CDCDCD; padding: 8px; ">
<legend><strong>Uploadify Sample</strong></legend>
<h2>Single File Upload</h2>
<p>Display speed</p>
<div id="fileUpload">You have a problem with your javascript</div>
</fieldset>
</body>
</html>
You can do it like this:
$("#fileUpload").fileUpload({
...
'onComplete': function(a, b, c, data, e){
alert(data);
}
});
Hope this helps. Cheers