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phpjqueryfancybox

fancybox :how to write this statement


How to include our path of image

<a href="image.jpg" data-fancybox="images" data-caption="My caption">
    <img src="thumbnail.jpg" alt="" />
</a>

I wrote code for image slideing while a click in iamge dynamicaly and i it giving me error

Parse error: syntax error, unexpected '' '' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' in D:\xampp\htdocs\PHP\gallery2.php on line 68

echo '  <a href='/IMAGES/".$image."' </a> ';
echo "<img src='IMAGES/".$image."'>  ";

what change should done to have proper image slide


Solution

  • Try This

    echo '<a href="/IMAGES/'.$image.'" data-fancybox="images" data-caption="My caption">.
    <img src="/IMAGES/'.$image.'" alt="" />
    </a>' 
    

    I am assuming /IMAGES/ is folder name not path