I have a map as such:
// map[int] position in string
// map[rune]bool characters possible at said position
func generateString(in map[int]map[rune]bool) []string {
// example: {0: {'A':true, 'C': true}, 1: {'E': true}, 2: {'I': true, 'X': true}}
result := []string{"AEI", "AEX", "CEI", "CEX"} // should generate these
return result
}
The difference with all possible permutations is that we are specifying which permutations are possible by index and I think that's the real head-breaker here.
First, we need to convert map[int]map[rune]bool
to []map[rune]bool
since map
iteration isn't guaranteed to be sorted by key's
After that, this is a recursive approach
var res []string
func dfs(curString string, index int, in []map[rune]bool) {
if index == len(in) {
res = append(res, curString)
return
}
for ch, is := range in[index] {
if !is { // I assume booleans can be false
return
}
dfs(curString+string(ch), index+1, in)
}
}
and we can call it with dfs("", 0, arr)
where arr
is given map
converted to slice
and answer will be in res
variable