I get a file with this commannd:
src = request.POST.get('src', '')
But the output is: https://url.com/path/filename.jpg
How can I just get path/filename.jpg?
regards Christopher
Yes I wrote a 3 lines command, one line would be better:
from urllib.parse import urlparse
import os
url = request.POST.get('src', '')
filepath = urlparse(url).path
src = path + (os.path.basename(filepath))