plotting data on a hexagonal figure

Question

I want to build a graph that will look like this, - for each point I have a single value and there is a maximum that reaches the border. All I can find is how to have hexbin in a scatterplot with seaborn or similar - any ideas, is there some ready solution maybe or I would need to code my way through it?

Answer 1

You could use tripcolor to show 6 shaded triangles. Scaling the outer vectors can adapt the triangles to show the desired proportions.

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.tri as tri

proportions = [0.6, 0.75, 0.8, 0.9, 0.7, 0.8]
labels = ['alpha', 'beta', 'gamma', 'delta', 'epsilon', 'zeta']
N = len(proportions)
proportions = np.append(proportions, 1)
theta = np.linspace(0, 2 * np.pi, N, endpoint=False)
x = np.append(np.sin(theta), 0)
y = np.append(np.cos(theta), 0)
triangles = [[N, i, (i + 1) % N] for i in range(N)]
triang_backgr = tri.Triangulation(x, y, triangles)
triang_foregr = tri.Triangulation(x * proportions, y * proportions, triangles)
cmap = plt.cm.rainbow_r  # or plt.cm.hsv ?
colors = np.linspace(0, 1, N + 1)
plt.tripcolor(triang_backgr, colors, cmap=cmap, shading='gouraud', alpha=0.4)
plt.tripcolor(triang_foregr, colors, cmap=cmap, shading='gouraud', alpha=0.8)
plt.triplot(triang_backgr, color='white', lw=2)
for label, color, xi, yi in zip(labels, colors, x, y):
    plt.text(xi * 1.05, yi * 1.05, label,  # color=cmap(color),
             ha='left' if xi > 0.1 else 'right' if xi < -0.1 else 'center',
             va='bottom' if yi > 0.1 else 'top' if yi < -0.1 else 'center')
plt.axis('off')
plt.gca().set_aspect('equal')
plt.show()

The code allows for different numbers of triangles. Here are examples with 5 or 6 triangles: