How to use result in IF to spit out True/False?

Question

The following code snippet

if pyautogui.locateOnScreen('test4x4.png', region = (200,200,4,4)) == "Box(left=200, top=200, width=4, height=4)":
    print("Found")
else:
    print("NotFound")

spits out NotFound, but

print(pyautogui.locateOnScreen('test4x4.png', region = (200,200,4,4)))

prints out "Box(left=200, top=200, width=4, height=4)". How to properly match the result so I can get the Found value back?

Answer 1

The locateOnScreen function returns a pyscreeze.Box object, not a string.

So you'll want to convert it to a tuple before doing any comparisons:

box = pyautogui.locateOnScreen('test4x4.png', region = (200,200,4,4))

if box is not None and tuple(box) == (200, 200, 4, 4):
    print("Found")
else:
    print("NotFound")

<Edit>

The reason you are getting TypeError: 'NoneType' object is not iterable, is because if the image is not found, locateOnScreen returns None. Trying to convert None to a tuple: tuple(None) throws an error.

You can protect against this by checking that box isn't None, as I've edited above.

I can't explain why you're still getting the error when the image is successfully found however, so you'll need to give some more info for us to solve that.

</Edit>

The reason your version doesn't work is because when you call print(box), behind the scenes the print function is actually calling str(box) and printing that instead.

Thats why even though

>>> print(box)
Box(left=200, top=200, width=4, height=4)

it doesn't mean that

box == "Box(left=200, top=200, width=4, height=4)"