How to not repeat permutations of i and j in “i not equal to j” loop in Python?

Question

An exhaustive “i not equal to j” loop typically starts out as

for i in range(t):
    for j in range(t):
        if i is not j:

To avoid repeating symmetric results (i.e. any i with j just gives the same answer as j with i), how can we additionally skip over these permuted instances in the loop above?

Answer 1

for i in range(t):
    for j in range(i, t):
        if i != j:

This guarantees that j >= i, so, therefore, there will be no i with j and j with i duplicates.

Alternatively,

for i in range(t):
    for j in range(i + 1, t):

Will exclude i j combinations where i == j, as j > i