How to create table entries with unique id and access them using that id..?

Question

Hi I need to create a table in lua with each entry(record) can be represented by unique id

table[p1d2].seq={0,1,2,3} table[p1d2].days={'sun','mon','wed'}
table[p2d2].seq={0,1,2,3,4} table[p2d2].days={'fri','sat','tue'}

print(table.concat(table[p1d2].seq))==> 0123

like that i want to insert and access please help me in solving this riddle

Answer 1

I'm not sure to understand what you're asking for, since tables in Lua natively handle string indexes, for example the following snippet:

tab = {};
tab['one']=1;
print(tab['one']);

prints 1...if that is not what you're asking, could you please try to explain more precisely what behavior you want?

And if that was your question, a code like this one should work (I defined a Thing class since I see you seem to use a class with seq and days fields, but I guess you already have something of the kind in your code, so I only left it for informational purposes).

-- class definition
Thing = {seq = {}, days ={}}

function Thing:new (o)
  o = o or {}
  setmetatable(o, self)
  self.__index = self
  return o
end

-- definition of the table and IDs

tab={}
p1d2='p1d2'
p2d2='p2d2'

-- this corresponds to the code you gave in your question

tab[p1d2]=Thing:new()
tab[p2d2]=Thing:new()
tab[p1d2].seq={0,1,2,3}
tab[p1d2].days={'sun','mon','wed'}
tab[p2d2].seq={0,1,2,3,4}
tab[p2d2].days={'fri','sat','tue'}

print(table.concat(tab[p1d2].seq))
-- prints '0123'