Using Try-Catch-Finally to handle arithmetic exceptions

Question

I would like to try TWO different things (both have a strong possibility of failure) and for this reason I would like to use the "finally" statement to run a "safety" just in case the first two tries both fail.

Take the following example (no this is not the code I am using in my project!).

int zero = 0;
int one = 1;

try
{
    // Throws ' cannot divide by zero ' error
    int error = one / zero;
}

catch
{
    // Throws error again of course
    int somenum = one / zero;
}

finally 
{
    MessageBox.Show("I can never make it here ..."); 
}

So, I would like for my program to do the following:

1. Attempt to divide by zero
2. If step #1 fails, I would like for the 'catch' statement to run its code (which should once again fail in this example).
3. IF both steps #1 and #2 fail, I would like for my program to display the MessageBox in the 'finally' statement.

Am I even close with this one?

Answer 1

int zero = 0;
int one = 1;

try {
    try
    {
        // Throws ' cannot divide by zero ' error
        int error = one / zero;
    }

    catch (DivideByZeroException)
    {
        // Throws error again of course
        int somenum = one / zero;
    }
}
catch (DivideByZeroException)
{
    MessageBox.Show("I can never make it here ...");
}