I'm trying to "select" the link from the onclick attribute in the following portion of html
<span onclick="Javascript:document.quickFindForm.action='/blah_blah'"
class="specialLinkType"><img src="blah"></span>
but can't get any further than the following XPath
//span[@class="specialLinkType"]/@onclick
which only returns
Javascript:document.quickFindForm.action
Any ideas on how to pick out that link inside of the quickFindForm.action
with an XPath?
I tried the XPath in a Java application and it worked ok:
import java.io.IOException;
import java.io.StringReader;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class Teste {
public static void main(String[] args) throws Exception {
Document doc = stringToDom("<span onclick=\"Javascript:document.quickFindForm.action='/blah_blah'\" class=\"specialLinkType\"><img src=\"blah\"/></span>");
XPath newXPath = XPathFactory.newInstance().newXPath();
XPathExpression xpathExpr = newXPath.compile("//span[@class=\"specialLinkType\"]/@onclick");
String result = xpathExpr.evaluate(doc);
System.out.println(result);
}
public static Document stringToDom(String xmlSource) throws SAXException, ParserConfigurationException, IOException {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
return builder.parse(new InputSource(new StringReader(xmlSource)));
}
}
Result:
Javascript:document.quickFindForm.action='/blah_blah'