I am trying to group the words_count
column by both essay_Set
and domain1_score
and adding the counters in words_count
to add the counters results as mentioned here:
>>> c = Counter(a=3, b=1)
>>> d = Counter(a=1, b=2)
>>> c + d # add two counters together: c[x] + d[x]
Counter({'a': 4, 'b': 3})
I grouped them using this command:
words_freq_by_set = words_freq_by_set.groupby(by=["essay_set", "domain1_score"])
but do not know how to pass the Counter addition function to apply it on words_count
column which is simply +
.
Here is my dataframe:
GroupBy.sum
works with Counter objects. However I should mention the process is pairwise, so this may not be very fast. Let's try
words_freq_by_set.groupby(by=["essay_set", "domain1_score"])['words_count'].sum()
df = pd.DataFrame({
'a': [1, 1, 2],
'b': [Counter([1, 2]), Counter([1, 3]), Counter([2, 3])]
})
df
a b
0 1 {1: 1, 2: 1}
1 1 {1: 1, 3: 1}
2 2 {2: 1, 3: 1}
df.groupby(by=['a'])['b'].sum()
a
1 {1: 2, 2: 1, 3: 1}
2 {2: 1, 3: 1}
Name: b, dtype: object