I am using Python, attempting Problem 17 of the Euler Project (adding up the number of letters in each number up to 1000).
I have written code to turn each number into a string and systematically work out how many letters each number contains, this code is not attractive, but it is mine. Here is the specific part I am having an issue with:
if len(n)==2:
print(n,n[1])
if n[0]=="0":
n=n[1]
if n[1]=="0":
if n[0]=="1":
cnt+=3
n=""
That print statement is there to show me what the code is trying to read. It works perfectly from 1 to 100, then when it attempts 101 I get an error for line 23 (if n[1]=="0":) saying the string index is out of bounds, but that print function is returning 01 1 which means it is able locate index 1 of this string.
Any ideas?
This is the full code, it's not very attractive, but it's mine.
def numletcount(t):
n=str(t)
cnt=0
while len(n)>0:
if n == "0":
n=""
if len(n)==1:
if n == "1" or n == "2" or n == "6":
cnt+=3
n=""
if n == "4" or n == "5" or n == "9":
cnt+=4
n=""
if n == "3" or n == "7" or n == "8":
cnt+=5
n=""
if len(n)==2:
print(n,n[1])
if n[0]=="0":
n=n[1]
if n[1]=="0":
if n[0]=="1":
cnt+=3
n=""
elif n[0] == "2" or n[0] == "3" or n[0] == "8" or n[0] == "9":
cnt+=6
n=""
elif n[0] == "4" or n[0] == "5" or n[0] == "6":
cnt+=5
n=""
elif n[-2] == "7":
cnt+=7
n=""
else:
if n[0]=="1":
if n[-1] == "1" or n[-1] == "2":
cnt+=6
n=""
elif n[-1] == "5" or n[-1] == "6":
cnt+=7
n=""
elif n[-1] == "3" or n[-1] == "4" or n[-1] == "8" or n[-1] == "9":
cnt+=8
n=""
elif n[-1] == "7":
cnt+=9
n=""
elif n[0] == "2" or n[0] == "3" or n[0] == "8" or n[0] == "9":
cnt+=6
n=n[-1]
elif n[0] == "4" or n[0] == "5" or n[0] == "6":
cnt+=5
n=n[-1]
elif n[0] == "7":
cnt+=7
n=n[-1]
if len(n)==3:
if n[1:3] == "00":
cnt+=7
n=n[0]
else:
if n[0] == "1" or n[0] == "2" or n[0] == "6":
cnt+=13
n=n[1:3]
elif n[0] == "4" or n[0] == "5" or n[0] == "9":
cnt+=14
n=n[1:3]
elif n[0] == "3" or n[0] == "7" or n[0] == "8":
cnt+=15
n=n[1:3]
if len(n)==4:
cnt+=11
n=n[1:4]
print(t,cnt)
return cnt
you said that its print 01 and 1, so n is 01 and n[0]==0. now you have
if n[0]=="0":
n=n[1]
so n is "1" now, and his length is 1