*I apologize, my tables displayed correctly when I was writing this question and after publishing the formatting looks off. trying to fix that now
I am trying to write a query in postgresql that would return, for any given child value, the nearest parent value that has reached a certain rank. Currently, I have this query, which displays the entire hierarchical path for any given child value-
WITH RECURSIVE tree AS (
SELECT "ChildDisplayID",
"ParentID",
"Rank",
1 as level
FROM table1
WHERE "ChildDisplayID" = {{some ChildID}}
UNION ALL
SELECT t1."ChildDisplayID",
t1."ParentID",
t1."Rank",
t.level + 1
FROM table1 t1
JOIN tree t ON t."ParentID" = t1."ChildDisplayID"
)
SELECT *
FROM tree
What I want to do is have in a single row that displays the child ID and the parent ID of the nearest parent whose rank is "Partner". For example, here is the output I am currently getting:
| ChildID | ParentID | Rank | Level |
|---------|----------|------|-------|
| 6 | 5 |Associate Manager| 1 |
| 5 | 4 |Manager| 2 |
| 4 | 3 |Associate Partner| 3 |
| 3 | 2 |Partner| 4 |
| 2 | 1 |Partner| 5 |
| 1 | |CEO| 6 |
Here is the output I want:
|ChildID | Nearest Partner | Rank |
|--------|----------|------|
|6 |3 | Partner |
What is the best way to do this?
You can put a stop condition on the first matching partner in the recursion, then filter the result:
WITH RECURSIVE tree AS (
SELECT "ChildDisplayID" as initialid, "ChildDisplayID", "ParentID", "Rank", 1 as level
FROM table1
WHERE "ChildDisplayID" = {{some ChildID}}
UNION ALL
SELECT t.initialid, t1."ChildDisplayID", t1."ParentID", t1."Rank", t.level + 1
FROM table1 t1
INNER JOIN tree t ON t."ParentID" = t1."ChildDisplayID"
WHERE t."Rank" <> 'Partner'
)
SELECT *
FROM tree
WHERE "Rank" = 'Partner'
It seems like you have a hierarchy where each child has just one parent, so there should be only one match, or no match at all.