How I write a clean condition from a "complex" combinations of conditions with && or ||

Question

For example, a have two statement conditions:

First, something similar to

const condition1 = value === '' && value1 === '' && value2 === '' && valu3e === '' && value4 === '' && value5 === ''

and second conditions more simple like

const condition2 = value === 'error'

and my if the statement has the two like this:

if (condition1 || condition2) {
....
}

Has any way to make this better than the actual implementation?

Answer 1

First condition :

const value = '',
  value1 = '',
  value2 = '',
  value3 = '',
  value4 = '',
  value5 = '';

const condition1 = [
  value,
  value1,
  value2,
  value3,
  value4,
  value5,
].every(x => x === '');

console.log(`Condition1 : ${condition1}`);

---

If you can refactor the values to be an array it would be better.

const values = [
  '',
  '',
  '',
  '',
  '',
  '',
];

const condition1 = values.every(x => x === '');

console.log(`Condition1 : ${condition1}`);

---

Altogether

const value = '',
  value1 = '',
  value2 = '',
  value3 = '',
  value4 = '',
  value5 = '';
  
if ([
  value,
  value1,
  value2,
  value3,
  value4,
  value5,
].every(x => x === '') || value === 'error') {
  console.log(`Condition : true`);
} else {
  console.log(`Condition : false`);
}