How to get href from class using python?

Question

I want to get link from href from an element. I tried find_elements_by_css_selector but can't reach out it. Does anyone know how to do it?

<a class="name" title="Download" data-i18n="[title]clickToDownload" data-src="some-link" href="link-to-retreive">
</a>

Answer 1

To print the value of the href attribute you can use either of the following Locator Strategies:

• Using css_selector:

  print(driver.find_element_by_css_selector("a.name[title='Download']").get_attribute("href"))
  

• Using xpath:

  print(driver.find_element_by_xpath("//a[@class='name' and @title='Download']").get_attribute("href"))
  

---

Ideally you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

• Using CSS_SELECTOR:

  print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a.name[title='Download']"))).get_attribute("value"))
  

• Using XPATH:

  print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[@class='name' and @title='Download']"))).get_attribute("value"))
  

• Note : You have to add the following imports :

  from selenium.webdriver.support.ui import WebDriverWait
  from selenium.webdriver.common.by import By
  from selenium.webdriver.support import expected_conditions as EC