How to convert a string in variable in shell

Question

set lamdrills = ("drill_1-2" drill_2-3")
set drill_1_2_fill_layers = ("cvf1") #input from other files
set span = `echo "$lam_drl" | cut -f2 -d'_'`
set startspan = `echo "$span" | cut -f1 -d'-'`
set endspan = `echo "$span" | cut -f2 -d'-'`
set fill_layers = `echo drill_"$startspan"_"$endspan"_fill_layers`

I want assign the drill_1_2_fill_layers to the fill_layers

Answer 1

It looks vaguely like you are looking for

set lamdrills = ("drill_1-2" "drill_2-3")  # typo fixed
foreach drill ($lamdrills)                 # loop over array
  set fill_layers = drill_`echo $drill | sed 's/.*_//;s/-/_/'`_fill_layers
  # ... use this variable
end

The C shell is tricky and unpopular (for good reasons); perhaps you would like to use a Bourne-compatible shell instead?

for drill in "drill_1-2" "drill_2-3"; do
  fill_layers="drill_$(echo "$drill" | sed 's/.*_//;s/-/_/')_fill_layers"
  # ... use "$fill_layers"
done

Of course, even better would be if the labels you use would use the same conventions and punctuation patterns consistently.