Solve "integer division in floating-point context" warning

Question

How does one solve the "integer division in floating-point context" warning, in this line of code:

int fps = 60;
double timePerTick = 1000000000 / fps;

Answer 1

When dividing two ints, you'll be using integer division, and only then promoting the result to a double, losing all the precision after the decimal point. You can use floating point precision by using a double literal instead:

double timePerTick = 1000000000.0 / fps;
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