I have a list of letters called liste
, and a vector called myvec
, a dataframe and another vector ind1
as follow
###############
## my sample ##
###############
liste=LETTERS[seq( from = 1, to = 10 )]
df1=data.frame(ID1=seq(from=1,to=3,by=1),
A=c(rep(1,3)),
B=c(rep(2,3)),
D=c(rep(3,3)),
F=c(rep(4,3)),
G=c(rep(5,3)))
myvec=c("A","B","G")
ind1=c(1,2,2,3,5,6)
names(ind1)=c("ID2","A","B","C","D","G")
ind1
ID2 A B C D G
1 2 2 3 5 6
df1
ID1 A B D F G
1 1 1 2 3 4 5
2 2 1 2 3 4 5
3 3 1 2 3 4 5
liste
"A" "B" "C" "D" "E" "F" "G" "H" "I" "J"
What i want to do is (i figured it out the 3 first checks while writing the post but not the last):
1- check if names of df1
are in myvec
: for my example it will give TRUE because of A B G
.
2- check if myvec
is contained in liste
then i would like to keep in my df1
only the subset of names that verify this condition.
3- do the same 2 checks for my vector ind1
.
I was able to do the 3 checks but not the last one for ind1
.
the expected output will be :
# check 1
# no problem
any(myvec %in% names(df1))
[1] TRUE
# check 2
# no problem
if(any(myvec %in% liste)){
df1=cbind(df1[1],df1[,names(df1) %in% myvec])
}
ID1 A B G
1 1 1 2 5
2 2 1 2 5
3 3 1 2 5
# check 3
# no rpoblem
any(myvec %in% names(ind1))
[1] TRUE
# check 4
# where i got stocked i tried to repeat the same code in check 2 but i got an error for dimension in vector
# expected output
ind1
ID2 A B G
1 2 2 6
Any help will be appreciated or resources about handling names in vectors. Thank you in advance
Is this what you are looking for?
if(any(myvec %in% liste)){
ind1=c(ind1[1],ind1[names(ind1) %in% myvec])
}