How can I combine two (or more) preg_replace's - PHP

< EDIT >

I Wanted to give a big thank you to all of you who have provided an answer, You have all given me great options. I will play with each and see which one suits my exact needs prior to selecting an answer. I do appreciate all of your responses though, everyone has a different approach to things. =)

bbcodes can (but not always do) include options, an example would be:

[URL="http://google.com"]GOOGLE[/URL]

</ EDIT >

I am currently hiding multiple variables from my string using the following method:

$result = preg_replace('/\[img\](.*)\[\/img\]/im', 'REPLACED', $qry);
$result = preg_replace('/\[url.*\](.*)\[\/url\]/im', 'REPLACED', $qry);

This works, but I would like to be able to do this with just one preg replace, and easily be able to add to it in the future if needed.

I have attempted to use:

$result = preg_replace("#\[/?(img|url)(=\s*\"?.*?\"?\s*)?]#im", 'REPLACED', $qry);

Which is only hiding the tags themselves.

How can I combine these replaces?

Solution

You can use

preg_replace('~\[(img|url)\b[^]]*](.*?)\[/\1]~is', 'REPLACED', $qry);

The regex matches:

\[ - a [ char
(img|url) - Group 1: img or url
\b - a word boundary
[^]]* - 0 or more chars other than ]
] - a ] char
(.*?) - Group 2: any zero or more chars, as few as possible
\[/\1] - [/, the same contents as in Group 1, and a ].

See the PHP demo:

$qry = '[url="google.com"]google[/url] and [img]image here[/img]';
echo preg_replace('~\[(img|url)\b[^]]*](.*?)\[/\1]~is', 'REPLACED', $qry);
// => REPLACED and REPLACED