In the example given in Oracle Docs, there is a way to create a polygon with a hole with the following syntax:
SDO_GEOMETRY(
2003, -- two-dimensional polygon
NULL,
NULL,
SDO_ELEM_INFO_ARRAY(1,1003,1, 19,2003,1), -- polygon with hole
SDO_ORDINATE_ARRAY(2,4, 4,3, 10,3, 13,5, 13,9, 11,13, 5,13, 2,11, 2,4,
7,5, 7,10, 10,10, 10,5, 7,5)
)
In my case, I have two SDO_GEOMETRY created as follows:
SELECT sdo_util.circle_polygon (longitude_1,
latitude_1,
r_1,
tol)
INTO inner_circle_geom
FROM DUAL;
SELECT sdo_util.circle_polygon (longitude_2,
latitude_2,
r_2,
tol)
INTO outer_circle_geom
FROM DUAL;
How can I create the polygon with a hole using the two geometries above?
I've tried using
...
SDO_ORDINATE_ARRAY(outer_circle_geom.sdo_ordinates, inner_circle_geom.sdo_ordinates)
But I receive the error
PLS-00306: wrong number or types of arguments in call to 'SDO_ORDINATE_ARRAY'
EDIT: the Oracle version is 10g
MT0's thought is right. You can use select sdo_geom.sdo_difference(
sdo_util.circle_polygon (longitude_2, latitude_2,r_2, tol),
sdo_util.circle_polygon (longitude_1, latitude_1,r_1, tol), tol)
from dual;