How to translate enumerate() to a for loop in Python

Question

I have the following code which finds the index of a guessed number from a long number, however I cannot use enumerate. What would the equivalent for loop look like for this:

guess = input()
long_number = ('5666')
a = [i for i, number in enumerate(long_number) if number == guess]
print(a)

e.g. Output: if guess = 5, then the output should be [0].

How would you do this using while, for and/or if functions only?

Answer 1

You can simply change the list comprehension to:

a = [i for i in range(len(long_number)) if long_number[i] == guess]

(in your code):

guess = input()
long_number = '5666'
a = [i for i in range(len(long_number)) if long_number[i] == guess]
print(a)

The output will be identical to yours