List Comprehension nested in Dict Comprehension

Question

I want to create a dict with lists as values, where the content on the lists depends on whether or not the key (numbers 1 to 100) is dividable by 3,5 and/or 7

The output would be like this:

{
    1: ['nodiv3', 'nodiv5', 'nodiv7'],
    3: ['div3', 'nodiv5', 'nodiv7'],
    15: ['div3', 'div5', 'nodiv7'],
}

Similar questions where about filtering the list/values, not creating them.

dict_divider = {}
for x in range(0,101):
    div_list= []
    if x % 3 == 0:
        div_list.append('div3')
    else:
        div_list.append('nodiv3')
    if x % 5 == 0:
        div_list.append('div5')
    else:
        div_list.append('nodiv5')
    if x % 7 == 0:
        div_list.append('div7')
    else:
        div_list.append('nodiv7')
    dict_divider[x] = div_list

This works just fine, but is there a way to do this with a pythonic one-/twoliner?

Something along like this: d = dict((val, range(int(val), int(val) + 2)) for val in ['1', '2', '3'])

Answer 1

There is actually a one liner that isnt even that complicated :)

my_dict = {}
for i in range(100):
    my_dict[i] = ['div' + str(n) if i % n == 0 else 'nodiv' + str(n) for n in [3,5,7]]