My version is interested in the name, age, origin and subject of students.
solve :-
length(X, 6), % there are six students
member([manuel, 19, _, _], X), % Manuel is 19 years old
member([_, 20, _, win], X), % 20 years old student studies win
...
But there are rules I don't know how to implement in Prolog. For example:
Oliver is two years older than the math student but two years younger than the student from Washington.
How do I create a rule where I can compare the age like that?
member([oliver,OLIVER_AGE,_,_],X) ,
member([_,MATH_AGE,_,math],X) ,
member([_,WASHINGTON_AGE,washington,_],X) ,
OLIVER_AGE is MATH_AGE + 2 ,
OLIVER_AGE is WASHINGTON_AGE - 2