Using the idl source containing the MIDL 3.0 simple type Char:
namespace BrokenMIDL_Char
{
[default_interface]
runtimeclass MainPage : Windows.UI.Xaml.Controls.Page
{
MainPage();
Int32 MyProperty;
Char MyStationLetter_1;
//Char MyStationLetter_2;
//Char MyStationLetter_3;
}
}
And the supporting functions
wchar_t MyStationLetter_1()
{
throw hresult_not_implemented();
}
void MyStationLetter_1(wchar_t /*value*/)
{
throw hresult_not_implemented();
}
char16_t MyStationLetter_2()
{
throw hresult_not_implemented();
}
void MyStationLetter_2(char16_t /*value*/)
{
throw hresult_not_implemented();
}
char MyStationLetter_3()
{
throw hresult_not_implemented();
}
void MyStationLetter_3(char /*value*/)
{
throw hresult_not_implemented();
}
Results in an error
T must be a WinRT type
My understanding was that the MIDL 3.0 types are the definition the WinRT types.
The MIDL compiler emits:
//------------------------------------------------------------------------------
// <auto-generated>
// This code was generated by a tool.
//
// Changes to this file may cause incorrect behavior and will be lost if
// the code is regenerated.
// </auto-generated>
//------------------------------------------------------------------------------
template<typename TDeclaringType, typename TValue>
void SetValueTypeMember_MyStationLetter_1(
::winrt::Windows::Foundation::IInspectable const& instance,
::winrt::Windows::Foundation::IInspectable const& value)
{
instance.as<TDeclaringType>().MyStationLetter_1(::winrt::unbox_value<TValue>(value));
}
During testing, I have a solution you could make a try.
You could open the Property tab > Properties > Configuration Properties > C/C++ > Language, find Treat Wchar_t As Built in Type property and select the No(/Zc:wchar_t-) option. Then, try to build your project.