Odoo 12. How to convert Binary File to Zip?

Question

I need to import a zip file that will contain only xml files.

My wizard looks like this:

class ZipImportsWizard(models.Model):
    _name = 'import.zip.dte'

    type = fields.Selection([('purchase', 'Purchases'),('sale', 'Sales'),], string="Type", default="purchase")
    file = fields.Binary(string='ZIP File', store=True)

I need to open this zip file and check the content. If the content is OK, I have to send this to another method.

The problem is, when I upload the file, it converts to a Binary file, so I can't user zipfile library to work with it.

How can I convert this Binary file to a Zip file again to work with it?

Answer 1

I was able to find a solution by myself, but also thanks to @astronautlevel anwers in this Similar question

from odoo import fields, models, _
from odoo.exceptions import UserError, ValidationError
import zipfile
import tempfile

class ZipImportsWizard(models.Model):
    _name = 'import.zip.dte'

    type = fields.Selection([('purchase', 'Purchases'),('sale', 'Sales'),], string="Type", default="purchase")
    file = fields.Binary(string='ZIP File', store=True)
    file_name = fields.Char('File name')

    def read_files_from_zip(self):
        file = base64.decodestring(self.zip_file)
        fobj = tempfile.NamedTemporaryFile(delete=False)
        fname = fobj.name
        fobj.write(file)
        fobj.close()

        zipzip = self.zip_file
        f = open(fname, 'r+b')  
        data = f.read()
        f.write(base64.b64decode(zipzip))
        pos = data.find(b'\x50\x4b\x05\x06')
        f.seek(pos + 22)
        with zipfile.ZipFile(f, 'r') as zip_file: 
            # do some stuff
            
            f.close()

        return