Unpack items and count them with one step

Question

I'm trying to iterate over Xs and ys simultaneously unpacking them and using the enumerate() function to count the pairs, as shown the following code:

X = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16], [17, 18, 19, 20]]
Y = [[11, 21, 31, 41], [51, 61, 71, 81], [91, 101, 111, 121], [131, 141, 151, 161], [171, 181, 191, 201]]

index = 0
for x, y in zip(X, Y):

    print(f'{index }, {x}, {y}')

    index += 1

I'd like to save the index += 1 line, and be able to get all index, x and y in the for loop

What I've Tried:

• I've tried using enumerate function on the zip, but it requires me to unpack the x and y manually latter, as shown in the following code, and I'd like to save this line:

X = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16], [17, 18, 19, 20]]
Y = [[11, 21, 31, 41], [51, 61, 71, 81], [91, 101, 111, 121], [131, 141, 151, 161], [171, 181, 191, 201]]

for index, data in enumerate(zip(X, Y)):
    x, y = data
    print(f'{index}, {x}, {y}')

Desired Outcome:

The desired outcome may be seen in the following schematic pseudo-code:

#for index, x, y in zip(X, Y):
#    print(f'{index }, {x}, {y}')

What am I missing here?

Thanks in advance.

Answer 1

you can unpack the value returned by enumerate straight into the tuple (your pseudo-code just misses the brackets):

for index, (x, y) in enumerate(zip(X, Y)):
    print(f'{index}, {x}, {y}')

-->

0, [1, 2, 3, 4], [11, 21, 31, 41]
1, [5, 6, 7, 8], [51, 61, 71, 81]
...