Why doesn't the reverse function I defined execute properly?

Question

Why doesn't the renverser function (reverse) do the job and why does the program exit right after intitialising the table?

#include <stdio.h>
#include <stdlib.h>
void renverser(int t[])
{   int j,i,n;
    for(i=0,j=n-1;i<j;i++,j--)
    {
        int a=t[i];
        t[i]=t[j];
        t[i]=a;
    }
    for (i=0;i<n;i++)
    {
        printf("%d",t[i]);
    }
}

int main()
{   int i,n;
    float t[100];
    printf("donner le taille du tableau a renverser \n :");
    scanf("%d",&n);
    for (i=0;i<n;i++)
    {   printf("donner l'element %d: \n",i);
        scanf("%d",&t[i]);
    }
    renverser(t);
    return 0;
}

Answer 1

The function does not make a sense because the size of the passed array is unknown.

Moreover the function has undefined behavior because there is used uninitialized variable n.

And the type of the function parameter is int * while the passed argument expression has the type float *.

It seems you mean the following array declaration

int t[100];

And the function should do only one thing: reverse an array.

The result array you should output in main.

The function can be declared and defined the following way

void renverser( int t[], size_t n )
{
    for ( size_t i = 0; i < n / 2; i++ )
    {
        int tmp = t[i];
        t[i] = t[n - i - 1];
        t[n - i - 1] = tmp;
    }
}

and the function can be called like

renverser( t, n );