event when the left menu is opened in xamarin forms shell

Question

I am working with xamarin forms shell. I have 1 image and 1 label to assign the name and profile picture of the user. I want every time the menu opens (press the button or drag to the right) to update that value again, but I can't find any events related to it. Someone please help me badly

Answer 1

Since there is no and won't be events such OnFlyoutOpened OnFlyoutClosed, you can listen to your Shell PropertyChanged event, if the property is FlyoutIsPresented then execute your code:

public AppShell()
{
    InitializeComponent();
    PropertyChanged += Shell_PropertyChanged;
}

private void Shell_PropertyChanged(object sender, PropertyChangedEventArgs e)
{
    if (e.PropertyName.Equals("FlyoutIsPresented"))
        if (FlyoutIsPresented)
            OnFlyoutOpened();      //you will execute your code here
        else
            OnFlyoutClosed();
}

Depending on your requirement you will define OnFlyoutOpened() and OnFlyoutClosed() methods.

Thanks to @PureWeen guidance in discussion.