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pythonarrayssortingalphabetical

"rank" each character in a string by the index at which they appear in the alphabet

I don't know how to get for example from arr1 = ['johaj'] --> arr2 = ['2','4','1','0','3'] I'm not able to describe it very well what I mean so i hope you can understand it from this example. I need to get array of 'alphabetical indexes'.

I would be very grateful for solution, how can I do this in Python. Thank you

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Solution

  • This will work for you:

    arr1 = ['johaj']

arr2 = []
for item in arr1:
  origins = list(zip(item, list(range(len(item)))))
  origins.sort()
  ranks = list(range(len(item)))
  positioned = {origin:rank for origin, rank in zip(origins, ranks)}

  ranked = [None] * len(item)
  for origin in origins:
    ranked[origin[1]] = positioned[origin]
  arr2.append(ranked)

print(arr2)

    Output:

    [[2, 4, 1, 0, 3]]

    Because arr1 is an array, you have to iterate over that array to get each item. This means that arr2 will be a two-dimensional array that will return the ranks for each item in arr1. For example, if:

    arr1 = ['johaj', 'foo', 'bar']

    It will output:

    [[2, 4, 1, 0, 3], [0, 1, 2], [1, 0, 2]]