AWS Route53 - Adding Simple Record

Question

I am able to add "Weighted" A records for the AWS Route53 using the API, using [Weight: aws.Int64(weight)], it works great using the code below. But how to add "Simple" A record - I did not see an option for Simple?

    params := &route53.ChangeResourceRecordSetsInput{
    ChangeBatch: &route53.ChangeBatch{ // Required
        Changes: []*route53.Change{ // Required
            { // Required
                Action: aws.String("UPSERT"), // Required
                ResourceRecordSet: &route53.ResourceRecordSet{ // Required
                    Name: aws.String(name), // Required
                    Type: aws.String("A"),  // Required
                    ResourceRecords: []*route53.ResourceRecord{
                        { // Required
                            Value: aws.String(target), // Required
                        },
                    },
                    TTL: aws.Int64(TTL),
                    //Region: aws.String("us-east-1"),
                    Weight:        aws.Int64(weight),
                    SetIdentifier: aws.String("-"),
                },
            },
        },
        Comment: aws.String("Sample update."),
    },
    HostedZoneId: aws.String(zoneId), // Required
}

Answer 1

A 'Simple' record is just a phrasing inside the Web Console. Just leave the record without any Weight or Latency flag and it will be a standard DNS record inside Route53.

See the type ResourceRecordSet documentation, required fields are marked. The rest, like Weight are optional!

https://docs.aws.amazon.com/sdk-for-go/api/service/route53/#ResourceRecordSet

Pretty much the same as using the CLI (https://aws.amazon.com/premiumsupport/knowledge-center/simple-resource-record-route53-cli/), just port the same fields to the Go struct.