Assume I have the below text in the database.
$str = 'Test text http://hello-world.com Test text http://google.com/file.jpg?google=1 Test text https://hell.o.wor.ld/test?qwe=qwe Test text text text http://test.test/test hello all how are you I hope you all are fine ';
Now for this text, I want to add below utm_source and medium for all URL.
$utmUrl = "utm_source=source&utm_medium=email&utm_campaign=mycamp";
I already know that I can find all URL and do str_replace() but I want to do it with
preg_replace()
let me know if anyone knows any other solution
here the problem is some URL already have ? mark in URL so there I need to apped URL with & and where there is no ? there I need to append with ?
Edit Suggested by joy
Something like this.
$re ='/(?:(?:https?|ftp|file):\/\/|www\.|ftp\.)(?:\([-A-Z0-9+&@#\/%=~_|$?!:,.]*\)|[-A-Z0-9+&@#\/%=~_|$?!:,.])*(?:\([-A-Z0-9+&@#\/%=~_|$?!:,.]*\)|[A-Z0-9+&@#\/%=~_|$])/im';
$str = 'Test text http://hello-world.com Test text http://google.com/file.jpg?google=1 Test text https://hell.o.wor.ld/test?qwe=qwe Test text text text http://test.test/test hello all how are you I hope you all are fine ';
$utmUrl = "utm_source=source&utm_medium=email&utm_campaign=mycamp";
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
foreach ($matches as $match)
$str = preg_replace('%' . $match[0] . '%', $match[0] . (strpos($match[0], '?') !== false ? '&' : '?') . $utmUrl, $str);
var_dump($str);
Edit: With preg_replace_callback
$re = '/(?:(?:https?|ftp|file):\/\/|www\.|ftp\.)(?:\([-A-Z0-9+&@#\/%=~_|$?!:,.]*\)|[-A-Z0-9+&@#\/%=~_|$?!:,.])*(?:\([-A-Z0-9+&@#\/%=~_|$?!:,.]*\)|[A-Z0-9+&@#\/%=~_|$])/im';
$str = 'Test text http://hello-world.com Test text http://google.com/file.jpg?google=1 Test text https://hell.o.wor.ld/test?qwe=qwe Test text text text http://test.test/test hello all how are you I hope you all are fine ';
$utmUrl = "utm_source=source&utm_medium=email&utm_campaign=mycamp";
$str = preg_replace_callback($re, function ($match) use ($utmUrl) {
return $match[0] . (strpos($match[0], '?') !== false ? '&' : '?') . $utmUrl . ' ';
}, $str);
var_dump($str);
Old Answer.
Something like this.
$re = '%(https?://.*)\s%mU';
$str = 'Test text http://hello-world.com Test text http://google.com/file.jpg?google=1 Test text https://hell.o.wor.ld/test?qwe=qwe Test text text text http://test.test/test hello all how are you I hope you all are fine ';
$utmUrl = "utm_source=source&utm_medium=email&utm_campaign=mycamp";
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
foreach ($matches as $match)
$str = preg_replace('%' . $match[1] . '%', $match[1] . (strpos($match[1], '?') !== false ? '&' : '?') . $utmUrl, $str);
var_dump($str);
Edit: With preg_replace_callback
$re = '%(https?://.*)\s%mU';
$str = 'Test text http://hello-world.com Test text http://google.com/file.jpg?google=1 Test text https://hell.o.wor.ld/test?qwe=qwe Test text text text http://test.test/test hello all how are you I hope you all are fine ';
$utmUrl = "utm_source=source&utm_medium=email&utm_campaign=mycamp";
$str = preg_replace_callback($re, function ($match) use ($utmUrl) {
return $match[1] . (strpos($match[1], '?') !== false ? '&' : '?') . $utmUrl . ' ';
}, $str);
var_dump($str);