Input: a list of word_types e.g. ["verb", "adjective", "name", "noun]
Desired output: a dictionary of three words for each letter-word_type combination arranged by word_type.
i.e.
{"verbs" : ["Averb1", "Averb2", "Averb3"], [Bverb1, ...], ..., "adjectives" : ["Aadjective1","Aadjectives2", "Aadjectives3"] ... etc
Here's what I used to generate my data.
import string
A_to_Z = list(string.ascii_uppercase) # list of letters a-z
lettered_word_types = ["verb", "adjective", "name", "noun"]
class Lexicon:
def __init__(self, testing = True):
if testing == True:
for TYPE in lettered_word_types:
setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}
data = Lexicon().__dict__
The class serves no purpose, it simply obfuscates what you are doing. To transliterate your code to use a dict
directly, you just need:
result = {}
for TYPE in lettered_word_types:
result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}
So, just to show that this is indeed equivalent:
In [1]: import string
...: A_to_Z = list(string.ascii_uppercase) # list of letters a-z
...: lettered_word_types = ["verb", "adjective", "name", "noun"]
...:
...: class Lexicon:
...: def __init__(self, testing = True):
...: if testing == True:
...: for TYPE in lettered_word_types:
...: setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
...: self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}
...:
...:
...: data = Lexicon().__dict__
In [2]: result = {}
In [3]: for TYPE in lettered_word_types:
...: result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
...:
In [4]: result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}
In [5]: result == data
Out[5]: True