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dos

Need find command solution for ms-dos application?

I have some *.bat file containing find command to extract some particular line.

for example, if my input text file contains something like:

Login time : XX:XX
username - XXXXXX
Login time : YY:YY
username - YYYYYYY

using username lest say:

find /I "XXXXXX" input.txt | find /I "XXXXXX" > output.txt

I am able to get the username but not sure how to get the correct login time for only the searched user name?

Solution

  • find (and findstr) can't process line feeds. They handle each line on its own. So you have to write a script that remembers the last line, checks the current line for the searchstring and prints both the last line and the current line, if the searchstring is found.

    I used findstr instead of find, because it's more secure (find "XXXXXX" would also find XXXXXXY). See findstr /? for the switches i, x and c.

    @echo off
setlocal enabledelayedexpansion
set "search=xxxxxx"

for /f "delims=" %%a in (t.txt) do (
  echo %%a|findstr /ixc:"username - %search%" >nul && echo !lastline! %%a
  set "lastline=%%a"
)