Here is how to print numbers in word size. I can't make it work for byte size numbers.
.model small
.stack 100h
.data
num dw 300 ; <----- See below
numS db 6 dup(' '),'$'**
.code
mov ax, @data
mov ds, ax
mov ax, num
mov bx, 10
mov si, offset numS+5
cmp ax,0
jge next
neg ax
next:
mov dx,0
div bx
add dl, 48
mov [si], dl
dec si
cmp ax, 0
jne next
cmp num,0
jge sof
mov byte ptr[si], '-'
dec si
sof:
inc si
mov ah, 9
mov dx, si
int 21h
.exit
end
I changed num dw to num db but something is wrong in the code I tried to change bx ..
Can anyone change operand types to match because the program says it's the problem. I need this code to not use other methods like pop, push, ret.
The good news is that you can keep using the conversion that you have. If you change the line num dw 300 into something like num db 36, all you have to modify in the code is how you load the AX register. Instead of mov ax, num, you now write mov al, num cbw. (You're expecting signed numbers apparently!)
An all bytes solution is possible though:
mov ax, @data
mov ds, ax
mov al, num
mov bl, 10
mov si, offset numS+5
cmp al,0
jge next
neg al
next:
mov ah, 0
div bl ; Calculates AX / BL --> AL is quotient, AH is remainder
add ah, 48
dec si
mov [si], ah
cmp al, 0
jne next
cmp num, al ; AL == 0
jge sof
dec si
mov byte ptr [si], '-'
sof:
mov dx, si
mov ah, 09h ; DOS.PrintString
int 21h