There are two windows PRIMARY and SECONDARY, I want to open secondary window using a button widget on primary window. But problem is whenever I press that button secondary window is opened, doesn't matter if a secondary window is already opened or not.
I don't want this behaviour. I only want to allow only one instance of secondary window at a time. If a secondary window is already opened, a new secondary window should not be open.
How do I achieve that?
A simple example code is given below to describe the problem more accurately.
from tkinter import *
##############################################################################################
# Function to open secondary window
def fctn_to_open_sec_win():
secondary_window()
# Secondary window
def secondary_window():
window = Tk()
window.title('Secondary window')
window.geometry('300x200')
Label(window, text='\n\nThis is the secondary window.\n\n'
'There should be only one instance of it at a time.').pack()
window.mainloop()
# Primary window
def primary_window():
window = Tk()
window.title('Primary window')
window.geometry('400x300')
Button(window, text='Open Secondary window', command=fctn_to_open_sec_win).pack(pady=(30, 0))
window.mainloop()
##############################################################################################
if __name__ == '__main__':
primary_window()
Dont use tk.Tk()
twice in your code, use a tk.Toplevel
instead.
Use a flag to achive this, also you could use the Destroy event of tkinter.
import tkinter as tk
ontop = False
def setflag(event):
global ontop
ontop = False
def top():
global ontop
if not ontop:
top = tk.Toplevel()
top.bind('<Destroy>', setflag)
ontop = True
root = tk.Tk()
b = tk.Button(root,command=top)
b.pack()
root.mainloop()
With classes you could avoid the global statement and even better keepin track of the instances.