Search code examples
python-3.xlistdictionarytweepy

Search for a key,value in different lists which has different key orders

I am using tweepy to retrieve links in a json.I have extracted a list with dictionaries inside. Most of them are in the same pattern (same order for the keys and values) like below

[{'bitrate': 2176000, 'content_type': 'video/mp4', 'url': 'https://A_LINK'},
{'bitrate': 632000, 'content_type': 'video/mp4', 'url': 'https://B_LINK'}, 
{'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'}, 
{'bitrate': 832000, 'content_type': 'video/mp4', 'url': 'https://D_LINK'}]

There are two characteristics of above pattern:

1.{'bitrate': 2176000, 'content_type': 'video/mp4', 'url': 'https://A_LINK'} is at the FRONT of {'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'}

2.{'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'} is MISSING the key Bitrate

I want to find the url which has the bitrate of 2176000 (Which is https://A_LINK for the example),the below codes are working with above patterns which I can find https://A_LINK

link = next((item for item in x if item["bitrate"] == 2176000), None)

print(link["url"])

However, as {'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'} is MISSING the key Bitrate

It will cause errors in the below patterns.

[{'bitrate': 632000, 'content_type': 'video/mp4', 'url': 'https://A_LINK'},
{'bitrate': 832000, 'content_type': 'video/mp4', 'url': 'https://B_LINK'}, 
{'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'}, 
{'bitrate': 2176000, 'content_type': 'video/mp4', 'url': 'https://D_LINK'}]

For the above pattern,

{'bitrate': 2176000, 'content_type': 'video/mp4', 'url': 'https://D_LINK'} is located AFTER 'content_type': 'application/x-mpegURL'

Whenever I receive pattern like this, I receive error

KeyError: 'bitrate'

and I can't get the https://D_LINK AFTER {'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'}

Therefore I am asking, when I receive the 2nd list pattern,

is there a way to so-called "bypass" {'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'}

so that I can get the https://D_LINK at last which has the bitrate 2176000?

Thank you.

Solution

  • Is this what you're looking for?

    l = [
    {'bitrate': 632000, 'content_type': 'video/mp4', 'url': 'https://A_LINK'},
    {'bitrate': 832000, 'content_type': 'video/mp4', 'url': 'https://B_LINK'},
    {'content_type': 'application/x-mpegURL', 'url': 'https://C_LINK'},
    {'bitrate': 2176000, 'content_type': 'video/mp4', 'url': 'https://D_LINK'},
]

''.join([d["url"] for d in l if "bitrate" in d.keys() and d['bitrate'] == 2176000])

    Output:

    'https://D_LINK'