Why dont the escape sequences work in tuples when printed
x = ("a\n", "b\n", "c\n")
y = ("a\n" "b\n" "c\n")
print (x)
print(y)
Why does it print(x) return ('a\n', 'b\n', 'c\n') and print (y)
a
b
c
Because ("a\n", "b\n", "c\n") is a tuple, but ("a\n" "b\n" "c\n") is a string:
("a\n" "b\n" "c\n") is the same as "a\n" "b\n" "c\n" what is in turn the same as "a\nb\nc\n".
(The "Hello, world." string literal is possible to write as "Hel" "lo, wor" "ld.", no + between parts.)
Now, the print() function prints a non-string object (as e.g. your tuple) converting it first to a string applying its .__str()__ method (which produces the same result as the standard function str()).
The result of str(("a\n", "b\n", "c\n")) is the string "('a\\n', 'b\\n', 'c\\n')" — no newline characters in it, as you may see, it consists of these 21 characters:
( ' a \ n ' , ' b \ n ' , ' c \ n ' )
By contrast to this string representation of your tuple, your string ("a\n" "b\n" "c\n") alias "a\nb\nc\n" consist of 6 characters, and 3 of them are newline characters:
a \n b \n c \n