I am trying to get the namespace associated with the code actually running.
I created a template project using 'lein new app test':
(ns test.core
(:gen-class))
(defn -main
[& args]
(println (ns-name *ns*)))
When using the repl, *ns* evaluates to test.core:
echo "(-main)" | lein repl
nREPL server started on port 37435 on host 127.0.0.1 - nrepl://127.0.0.1:37435
REPL-y 0.4.4, nREPL 0.7.0
Clojure 1.10.1
OpenJDK 64-Bit Server VM 1.8.0_265-b01
Docs: (doc function-name-here)
(find-doc "part-of-name-here")
Source: (source function-name-here)
Javadoc: (javadoc java-object-or-class-here)
Exit: Control+D or (exit) or (quit)
Results: Stored in vars *1, *2, *3, an exception in *e
test.core=> (-main)
test.core
nil
test.core=> Bye for now!
But when using lein run, I get user namespace:
lein run
user
Why such a behavior ? How can I get the namespace of a piece of code like in the repl ?
A few things to note:
*ns*
is bound to the namespace wherein the expression is evaluateduser
is the default namespace(test.core/-main)
from the user
namespace, *ns*
is bound to user
, not test.core
.If you would like to print the namespace in which -main
was defined, you can use a top-level expression:
(ns test.core)
(def current-ns *ns*)
(defn -main [& args]
(println (ns-name current-ns)))
or use var metadata:
(ns test.core)
(defn -main [& args]
(println (ns-name (:ns (meta #'-main)))))