How to convert Python binary to ASCII

Question

I have a binary string encrypted with this: ( S is the binary string)

res = ''.join(format(ord(i), 'b') for i in s)

How to I decrypt it?

I tried the following but then the string is empty?

    for i in s:
      res += chr(int(str(i),2))
   print(res)

Answer 1

Use '07b' or '08b' in format while encoding to binary, as it will keep leading zeros and represent number in 7 or 8 bits which will make it easy to decode back. Now we will consider 8 bits at a time as each character is represented in 8 bits now. Use 7 everywhere if you happen to use '07b' in format. Ascii characters need 7 bits to be represented.

>>> s = "abcde"
>>> res = ''.join(format(ord(i), '08b') for i in s)
>>> ans = []
>>> for i in range(0, len(res), 8):
...      ans.append(chr(int(res[i:i+8],2)))
... 
>>> ''.join(ans)
'abcde'

One liner:

>>> ''.join([ chr(int(res[i:i+8],2)) for i in range(0,len(res),8)])
'abcde'

Reference:

Convert to binary and keep leading zeros in Python

Is ASCII code 7-bit or 8-bit?