I have the following tables:
CREATE TABLE
IF NOT EXISTS {}.roles_permissions
(
role_id INT
(12) NOT NULL,
permission_id INT
(12) NOT NULL,
UNIQUE KEY
(role_id,permission_id)
CONSTRAINT `fk-rprole` FOREIGN KEY
(`role_id`)
REFERENCES `roles`
(`id`)
ON
DELETE CASCADE
ON
UPDATE CASCADE
CONSTRAINT (`fs_rppermission`) FOREIGN KEY
(`permission_id`)
REFERENCES `permissions`
(`id`)
ON
DELETE CASCADE
ON
UPDATE CASCADE
)
and it thow a err:- You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'CONSTRAINT fs_rppermission
FOREIGN KEY
what's the problem?
Consider:
CREATE TABLE IF NOT EXISTS roles_permissions (
role_id INT(12) NOT NULL,
permission_id INT(12) NOT NULL,
UNIQUE KEY (role_id,permission_id),
CONSTRAINT `fk-rprole` FOREIGN KEY (`role_id`)
REFERENCES `roles`(`id`)
ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `fs_rppermission` FOREIGN KEY (`permission_id`)
REFERENCES `permissions` (`id`)
ON DELETE CASCADE ON UPDATE CASCADE
);
Rationale:
there are missing commas all over your statement
the name of the foreign should not be surrounded with parentheses
... proper formatting makes the statement easier to write and read