How to get the minimum and maxium number using pointers in C++

Question

I trying to find the minimum and maximum numbers using pointers in C++ but in this code that I get from the video-sharing site gives me the wrong value. when I type 1 2 3 4 5 6 its answer is the minimum is 2 and the maximum is 2.

Here is my code:

#include <iostream>
 using namespace std;
int main()
{
    int value[6], * maxi, * mini, a;
    cout << "Enter six numbers with space: ";
    for (int a = 0; a < 6; a++)
        cin >> *(value + a);
    maximum = value;
    minimum = value;
    for (i = 1; i < 6; i++)
    {
        if (*(value + i) > * maximum)
            *maximum = *(value + i);
    }
    for (i = 0; i < 6; i++)
    {
        if (*(value + i) < *minimum)
            *minimum = *(value+ i);
    }
    /* Print variable value with their memory address */
    cout << "Integer with the Maximum value = " << *minimum << ", Address of integer = " << &maximum  
 << endl;
    cout << "Integer with the minimum value = " << *minimum  << ", Address of integer = " << &minimum  
  << endl;
    return 0;
  }

this is the result of the code

Enter five (6) numbers separated by a space: 1 2 3 4 5 6

Integer with the largest value = 2, Address of integer = 00AFF9F4

Integer with the smallest value = 2, Address of integer = 00AFF9E8

Answer 1

Here you are the complete code:

#include <iostream>
#define N_VALUES 6

using namespace std;
int main()
{
    int value[N_VALUES], *maximum, *minimum, i;
    cout << "Enter six numbers with space: ";
    for (i = 0; i < N_VALUES; i++) cin >> *(value + i);
    
    maximum = value;
    minimum = value;
    
    for (i = 1; i < N_VALUES; i++) {
        if (*(value + i) > (*maximum)) {
            maximum = (value + i);
        }
    }
    
    for (i = 1; i < N_VALUES; i++) {
        if (*(value + i) < (*minimum)) {
            minimum = (value+ i);
        }
    }
    
    /* Print variable value with their memory address */
    cout << "Integer with the Maximum value = " << *maximum << ", Address of integer = " << maximum << endl;
    cout << "Integer with the minimum value = " << *minimum  << ", Address of integer = " << minimum << endl;
    return 0;
}