i dont understand with this error message from cronjob log
Status: 404 Not Found
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Content-type: text/html; charset=UTF-8
No input file specified.
this is my command in cronjob
cd /home/host/public_html && php register_argc_argv=1 artisan schedule:run >> /home/host/public_html/backup.log 2>&1
this is my schedule in kernel.php
protected function schedule(Schedule $schedule)
{
$schedule->call(function () {
$filename1 = base_path("/CSV/data.csv");
$filesize1 = filesize($filename1);
if($filesize1 > 0)
{
$file1 = fopen(base_path("/CSV/data.csv"), "r");
while (($getData1 = fgetcsv($file1, 10000, ";")) !== FALSE)
{
DB::table('tbdata')->insert([
'ID' => $getData1[0],
'Date_' => $getData1[1],
'Date' => $getData1[2],
'Status' => $getData1[3],
'Remark' => $getData1[4],
'SMS' => $getData1[5]
]);
}
fclose($file1);
unlink(base_path("/CSV/data.csv"));
}
})->daily();
}
Please help me
try
cd /home/host/public_html && php -d register_argc_argv=1 artisan schedule:run >> /home/host/public_html/backup.log 2>&1
To change ini config you need the option d
-d foo[=bar] Define INI entry foo with value 'bar'
it was trying to find the file register_argc_argv=1
and got 404