copy subfolder without parent folders

Question

I have the folder /a/b/c/d/ and I want to copy d/ into destination /dst/.

However, shutil.copytree("/a/b/c/d", "/dst") produces /dst/a/b/c/d.

I only want /dst, or even /dst/d would suffice, but I don't want all the intermediate folders.

[edit]

As others have noted, copytree does what I want - I had unintentionally added the full path of the source to my destination!

Answer 1

Given this file structure (on my directory /tmp):

a
└── b
    └── c
        └── d
            ├── d_file1
            ├── d_file2
            ├── d_file3
            └── e
                ├── e_file1
                ├── e_file2
                └── e_file3

If you do shutil.copytree("/tmp/a", "/tmp/dst") you will get:

dst
└── b
    └── c
        └── d
            ├── d_file1
            ├── d_file2
            ├── d_file3
            └── e
                ├── e_file1
                ├── e_file2
                └── e_file3

But if you do shutil.copytree('/tmp/a/b/c/d', '/tmp/dst/d') you get:

dst
└── d
    ├── d_file1
    ├── d_file2
    ├── d_file3
    └── e
        ├── e_file1
        ├── e_file2
        └── e_file3

And shutil.copytree('/tmp/a/b/c/d', '/tmp/dst'):

dst
├── d_file1
├── d_file2
├── d_file3
└── e
    ├── e_file1
    ├── e_file2
    └── e_file3

shutil.copytree also takes relative paths. You can do:

import os
os.chdir('/tmp/a/b/c/d')    
shutil.copytree('.', '/tmp/dst')

Or, since Python 3.6, you can use pathlib arguments to do:

from pathlib import Path
p=Path('/tmp/a/b/c/d')
shutil.copytree(p, '/tmp/dst')

Either case, you get the same result as shutil.copytree('/tmp/a/b/c/d', '/tmp/dst')