Create a function based on timeout in Swift

Question

I want to make a function that returns something within significant time. The function should return some predefined value if timeout. for example,

func loginFunc(timeOut: Int) {
        
    Login.getUSerAuthenticaiton(email: "[email protected]", password: "123456789", completion: {_,_ in 
            print("Reponse")
    })
}

call Function like,

loginFunc(timeOut: 10)

Means, the function should run for 10 seconds after that it should return nil. Make sure it will be an API call or it can be a normal funtion.

Answer 1

First way:

 let timer = Timer.scheduledTimer(withTimeInterval: 10, repeats: false) { timer in
       print("Time is Over")
    }
    Login.getUSerAuthenticaiton(email: "[email protected]", password: "123456789", completion: {_,_ in
            print("Reponse")
        timer.invalidate()
    })

You can invalidate timer if a response will faster than 10 sec and timer callback will never fired

Second way:

func loginFunc(timeOut: Int) {
    
    var isResponseGet = false
    
    let timer = Timer.scheduledTimer(withTimeInterval: 10, repeats: false) { timer in
        if isResponseGet {
            print("<##>Already get a rtesponse")
        } else {
            print("10 secs left and i didn't get a response")
        }
    }
    Login.getUSerAuthenticaiton(email: "[email protected]", password: "123456789", completion: {_,_ in
            print("Reponse")
        isResponseGet = true
    })
}