pythonnumberspidata-generation
Looking for a way to infinitely generate digits of PI
please correct me if this is a dumb and impossible problem, but is there a way to have a script that continually generates digits of PI? for example, the script could generate a digit of PI, then store it in a .txt file, then repeat, or simply print out the digits it generates.
Solution
This is using an iterative method !
#!/usr/bin/env python3
# https://github.com/MrBlaise/learnpython/blob/master/Numbers/pi.py
# Find PI to the Nth Digit
# Have the user enter a number 'n'
# and print out PI to the 'n'th digit
def calcPi(limit): # Generator function
"""
Prints out the digits of PI
until it reaches the given limit
"""
q, r, t, k, n, l = 1, 0, 1, 1, 3, 3
decimal = limit
counter = 0
while counter != decimal + 1:
if 4 * q + r - t < n * t:
# yield digit
yield n
# insert period after first digit
if counter == 0:
yield '.'
# end
if decimal == counter:
print('')
break
counter += 1
nr = 10 * (r - n * t)
n = ((10 * (3 * q + r)) // t) - 10 * n
q *= 10
r = nr
else:
nr = (2 * q + r) * l
nn = (q * (7 * k) + 2 + (r * l)) // (t * l)
q *= k
t *= l
l += 2
k += 1
n = nn
r = nr
def main(): # Wrapper function
# Calls CalcPi with the given limit
pi_digits = calcPi(int(input(
"Enter the number of decimals to calculate to: ")))
i = 0
# Prints the output of calcPi generator function
# Inserts a newline after every 40th number
for d in pi_digits:
print(d, end='')
i += 1
if i == 40:
print("")
i = 0
if __name__ == '__main__':
main()
