How could I group a list of strings into a list of different sublist

Question

I have a list of strings as the example below.

list = ['#4008 (Pending update)',
 'Age 1 Female',
 'Onset date',
 '-',
 '#4007 (Pending update)',
 'Onset date',
 'Asymptomatic',
 'Confirmed date',
 '-',
 '+'
 '#4006 (Pending update)',
 'Age 65 Female',
 'Onset date',
 '-',
 'Place of residence',
 '-']

I am going to group the strings into a sublists of list as below, where if a string is starting with '#' then I would group it with the strings behind it until the next string that starts with '#' appear.

[['#4008 (Pending update)',
 'Age 1 Female',
 'Onset date',
 '-'],

 ['#4007 (Pending update)',
 'Onset date',
 'Asymptomatic',
 'Confirmed date',
 '-',
 '+'],

['#4006 (Pending update)',
 'Age 65 Female',
 'Onset date',
 '-',
 'Place of residence',
 '-']]

new_list = []
sub_list
n = 0
for i in list:
    if i[0].startswith('#'):
        try i[0+1].
        sub_list.append(i)

new_list.append(sub_list)
new_list

My idea is starting with the index 0 string and check strings one by one and break the loop when next string starts with # appear. Then the searching loop starts again to group the next sublist but I have no idea how to write the code now. How could it can be achived, thanks

Answer 1

lst = ['#4008 (Pending update)',
 'Age 1 Female',
 'Onset date',
 '-',
 '#4007 (Pending update)',
 'Onset date',
 'Asymptomatic',
 'Confirmed date',
 '-',
 '+',
 '#4006 (Pending update)',
 'Age 65 Female',
 'Onset date',
 '-',
 'Place of residence',
 '-']

out = []
for val in lst:
    if val.startswith('#'):
        out.append([val])
    else:
        out[-1].append(val)

from pprint import pprint
pprint(out, width=40)

Prints:

[['#4008 (Pending update)',
  'Age 1 Female',
  'Onset date',
  '-'],
 ['#4007 (Pending update)',
  'Onset date',
  'Asymptomatic',
  'Confirmed date',
  '-',
  '+'],
 ['#4006 (Pending update)',
  'Age 65 Female',
  'Onset date',
  '-',
  'Place of residence',
  '-']]