I am trying to select JSON properties as column. The properties that needs to be selected are stored in some other table
CREATE TABLE [Templates](
[ID] [int] NOT NULL,
[Template] [nvarchar](max)
)
INSERT INTO Templates(ID,Template)
VALUES
(1,'{"FirstName":"foo"}'),
(2,'{"FirstName":"joe","LastName":"dow"}'),
(3,'{"LastName":"smith","Address":"1234 Test Drive"}'),
(4,NULL)
Declare @SQL NVARCHAR(max)
--For brevity purpose i am hardcoding these property names. In reality column names will come from another table
DECLARE @properties NVARCHAR(max) = '[Address],[FirstName],[LastName]'
Set @SQL = '
Select '+ @properties +'
From (
Select T.ID
,j.[Key]
,j.[Value]
From Templates T
Cross Apply OpenJSON(T.Template) AS j
) src
Pivot ( max(value) for [Key] in ('+ @properties +') ) pvt
'
Exec(@SQL)
The code above is mostly working except for the Last row where Template
is NULL. (ID = 4)
Expected: The query should return 4 rows and for the last row, all columns should be null except ID.
CROSS APPLY
requires rows to be returned, however, Cross Apply OpenJSON(NULL) AS j
returns no rows. Use OUTER APPLY
:
' ...
OUTER APPLY OpenJSON(T.Template) AS j
...'
EXEC sp_executesql @SQL;
Note I also use sp_executesql
as you can't parametrise EXEC (@SQL)