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pythonlistoperators

python decompose a list


I remember I once seen a operator which is able to decompose a list in python.

for example

[[1],[2],[3]]

by applying that operator, you get

[1], [2], [3]

what is that operator, any help will be appreciated.


Solution

  • If you want to pass a list of arguments to a function, you can use *, the splat operator. Here's how it works:

    list = [1, 2, 3]
    function_that_takes_3_arguments(*list)
    

    If you want to assign the contents of a list to a variable, you can list unpacking:

    a, b, c = list # a=1, b=2, c=3