'or' boolean operation appearing faulty when comparing a string to two cases

Question

I have a simple code below that doesn't seem to output the expected result. The code only prints yup once even though I expect the code to print yup three times since that boolean expression will be true three times during the entire for loop iteration. Any advice on how to change my bool expression so that the loop prints yup three times?

a1=['555','666','777',66]
b1=['999','888','333',66]

for a,b in zip(a1,b1):
    if a == ('555'  or  '666' or 66):
        print('yup')

Answer 1

maybe this helps highlight your problem

x = ('555'  or  '666' or 66)
print(x)
a1=['555','666','777',66]
for a in a1:
    if a == x:
       print("yup")

the correct check is

either

if a in ('555'  or  '666' or 66)

or

if a == '555' or a == '666' or a == 66